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Question:
Find the roots of the 2x^2 x-6=0 , by factorizatoin
Answer:

Given, 2x2 + x - 6 = 0

=> 2x2 + 4x - 3x - 6 = 0

=> 2x(x + 2) - 3(x + 2) = 0

=> (x + 2) * (2x - 3) = 0

=> x + 2 = 0 and 2x - 3 = 0

=> x = -2, 3/2

So, the roots of the equation are: -2, 3/2

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